strpbrk

Locate characters in string,Returns a pointer to the first occurrence in str1 of any of the characters that are part of str2, or a null pointer if there are no matches.

The search does not include the terminating null-characters of either strings, but ends there.

在 dest 所指向的空终止字节串中，扫描来自 breakset 所指向的空终止字节串的任何字符，并返回指向该字符的指针。

检索字符串 dest 中第一个匹配字符串 breakset 中字符的字符，不包含空结束字符。也就是说，依次检验字符串 dest 中的字符，当被检验字符在字符串 breakset 中也包含时，则停止检验，并返回该字符位置。

若 dest 或 breakset 不是指向空终止字节字符串的指针则行为未定义。

char* strpbrk( const char* dest, const char* breakset );

Parameters

dest

C string to be scanned.

指向要分析的空终止字节字符串的指针

breakset

C string containing the characters to match.

指向含要搜索的字符的空终止字节字符串的指针

Return Value

A pointer to the first occurrence in str1 of any of the characters that are part of str2, or a null pointer if none of the characters of str2 is found in str1 before the terminating null-character.If none of the characters of str2 is present in str1, a null pointer is returned.

指向 dest 中首个亦在 breakset 中的字符的指针，或若这种字符不存在则为空指针。

该函数返回 dest 中第一个匹配字符串 breakset 中字符的字符数，如果未找到字符则返回 NULL。

名称代表“字符串指针打断 (string pointer break) ”，因为它返回指向首个分隔符（“打断”）的指针。

Example

//// Created by zhangrongxiang on 2018/2/6 11:18// File strpbrk//#include 
    
     #include 
     
      //依次检验字符串 str1 中的字符，当被检验字符在字符串 str2 中也包含时，则停止检验，并返回该字符位置。//检索字符串 str1 中第一个匹配字符串 str2 中字符的字符，不包含空结束字符。int main() {    int i = 0;    const char str1[] = "abcde2fghi3jk4l";    const char str2[] = "34";    const char *str3 = "Life is short,I use C";    char *ret;    ret = strpbrk(str1, str2);    if (ret) {        printf("Number one is : %c\n", *ret);//3    } else {        printf("No");    }    ret = strpbrk(str1, str3);    if (ret) {        printf("Number one is : %c\n", *ret);//e    } else {        printf("No");    }    printf("\n");    size_t len = strlen(str1);    char *ch = 0;    int index = 0;    char all[20] = {0};    //获取两个字符串的字符交集    for (; i < len; ++i) {        ret = strpbrk((str1 + sizeof(char) * (index + 1)), str3);        if (ret) {            ch = strrchr(str1, *ret);            index = (int) (ch - str1);            printf("Number one is : %c\n", *ret);            all[i] = *ret;        } else {            printf("No");        }    }    printf("\n");    for (i = 0; i < 20; ++i) {        if (all[i] == 0)            break;        printf("%c ", all[i]); //e f h i    }    printf("\n");    //单词统计    const char *str = "hello world, friend of mine!";    const char *sep = " ,!";    unsigned int cnt = 0;    do {        str = strpbrk(str, sep); // 寻找分隔符//        printf("%s\n",str);        if (str){            str += strspn(str, sep); // 跳过分隔符            printf("%s\n",str);        }        ++cnt; // 增加词计数    } while (str && *str);    printf("There are %d words\n", cnt); // 5    return 0;}